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(5m+4)^2=0

2 min read Jun 16, 2024
(5m+4)^2=0

Solving the Equation (5m + 4)^2 = 0

This equation represents a quadratic equation in disguise. Here's how to solve it:

Understanding the Equation

  • (5m + 4)^2 means (5m + 4) multiplied by itself: (5m + 4) * (5m + 4).
  • = 0 indicates we're looking for the values of 'm' that make the entire expression equal to zero.

Solving for 'm'

  1. Expand the square: (5m + 4)^2 = 25m^2 + 40m + 16

  2. Set the equation to zero: 25m^2 + 40m + 16 = 0

  3. Factor the quadratic expression: (5m + 4)(5m + 4) = 0

  4. Solve for 'm': 5m + 4 = 0 5m = -4 m = -4/5

Conclusion

The only solution to the equation (5m + 4)^2 = 0 is m = -4/5. This means that if you substitute -4/5 for 'm' in the original equation, the expression will equal zero.

It's important to note that this equation has a double root because the factor (5m + 4) appears twice. This signifies that the graph of the equation would touch the x-axis at the point (-4/5, 0) without crossing it.

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